Code: Select all
print(f "There are two chocolate, three vanilla, and four strawberry milkshakes. Without replacement, what is the chance of unknowingly picking a chocolate and then a vanilla?")
float(chocolate_shake) = 2/9
float(vanilla_shake) = 3/8
prob_of_this_scenario = chocolate_shake * vanilla_shake
percent_prob_of_this_scenario = prob_of_this_scenario * 100
print(f "The chance of unknowingly picking a chocolate and then a vanilla is {prob_of_this_scenario} which is {percent_prob_of_this_scenario}")
\(P(E_{1}) * P(E_{2}\,\, | \,\,E_{1}) ... *\,\,P(E_{n + 1}\,\, | \,\, E_{n}) \)
Given that:
\(P(E) = \dfrac{O_{F}}{O_{T}}\)
\(O_T \ne 0\)
Read: The dependent probability of event 1 and then event 2 and then event E_{n + 1} equals the probability of event 1 multiplied by the probability of event 2, given that event 1 already happened multiplied by event {n + 1}, given that event E_{n} already happened.
Given that
The probability of an event equals outcomes favored divided by outcomes total.
Outcomes total cannot equal zero
\(P_{D}(E_{1} \longrightarrow E_{2}) =There are two chocolate, three vanilla and four strawberry shakes. Without replacement, what is the chance of unknowingly picking a chocolate and then a vanilla?
P(E_{1}) * P(E_{2}\,\,|\,\,E_{1})\)
